A bicycle accelerates from rest at 0.025m/s². How long does it take the bicycle to acquire a speed of 34km/hr?

To find out how long it takes for the bicycle to acquire a speed of 34 km/h, we can use the basic equation of motion:

\[
v = u + at
\]

where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.

Here, we know:
- \( u = 0 \) m/s (since the bicycle starts from rest),
- \( a = 0.025 \) m/s²,
- \( v = 34 \) km/h.

First, we need to convert the final velocity from km/h to m/s:

\[
v = 34 \times \frac{1000}{3600} = 9.44 \text{ m/s}
\]

Now, substituting the values into the equation \( v = u + at \):

\[
9.44 \text{ m/s} = 0 \text{ m/s} + (0.025 \text{ m/s}^2) \times t
\]

Solving for \( t \):

\[
t = \frac{9.44 \text{ m/s}}{0.025 \text{ m/s}^2} = 377.6 \text{ seconds}
\]

So, it takes the bicycle **377.6 seconds** to acquire a speed of 34 km/h.

Would you like more details on this, or do you have any other questions?

Here are some related questions you might find interesting:
1. What would the distance traveled be during this acceleration?
2. How would the time change if the acceleration were doubled?
3. How would the final speed change if the time were halved?
4. What is the significance of uniform acceleration in this problem?
5. Can you calculate the average velocity during this period?
6. What other methods could be used to solve this problem?
7. How does this scenario change if the bicycle had an initial speed?
8. What is the physical meaning of acceleration in this context?

**Tip:** Always remember to check units carefully when solving physics problems to ensure they are consistent throughout the calculations.

Learn how to calculate the time it takes for a bicycle to accelerate from rest at 0.025 m/s² to a speed of 34 km/hr. This physics problem involves kinematics and uniform acceleration. Suitable for Grades 9-12.

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