1. គេត្រាំ បន្ទះ( Mg) ទៅក្នុងសូលុយស្យុង CuSO4 កំហាប់ 0.05M មាឌ 1L ក្រោយប្រតិកម្មគេឃើញបន្ទះ( Mg) កើនម៉ាស 6.25% នៃម៉ាសដែលបានយកមកប្រើ ដំបូង ។ 
 ក. គណនាម៉ាសបន្ទះ ( Mg) ដែលយកមកប្រើដំបូង ។ 
 ខ. គណនាម៉ាស ( Mg) ដែលមិនចូលរួមប្រតិកម្ម ។ គេឲ្យ ( Mg= 24 , Cu= 64 , O= 16 , S= 32 ) 
 Please tell me 

To solve the problem, we need to follow the steps methodically:

1. **Determine the initial mass of the \( \text{Mg} \) strip.**
2. **Calculate the mass increase of the \( \text{Mg} \) strip.**
3. **Use stoichiometry to determine the reactions and remaining mass of \( \text{Mg} \).**

### Given:
- Initial concentration of \( \text{CuSO}_4 \): \( 0.05 \, \text{M} \)
- Volume of \( \text{CuSO}_4 \) solution: \( 1 \, \text{L} \)
- Increase in mass of \( \text{Mg} \) strip: \( 6.25\% \)
- Molar masses: 
  - \( \text{Mg} = 24 \, \text{g/mol} \)
  - \( \text{Cu} = 64 \, \text{g/mol} \)
  - \( \text{O} = 16 \, \text{g/mol} \)
  - \( \text{S} = 32 \, \text{g/mol} \)

The reaction between magnesium and copper sulfate is:
\[ \text{Mg} + \text{CuSO}_4 \rightarrow \text{MgSO}_4 + \text{Cu} \]

### Part A: Calculate the initial mass of the \( \text{Mg} \) strip

Let's denote the initial mass of the \( \text{Mg} \) strip as \( m \).

Given that the mass increases by 6.25%, we have:
\[ m_{\text{final}} = m + 0.0625m = 1.0625m \]

This means the mass of copper deposited on the magnesium strip must equal the 0.0625m increase.

### Part B: Calculate the mass of \( \text{Mg} \) that did not react

From the stoichiometry of the reaction:
\[ \text{Mg} + \text{CuSO}_4 \rightarrow \text{MgSO}_4 + \text{Cu} \]

1 mole of Mg reacts with 1 mole of CuSO_4 to produce 1 mole of MgSO_4 and 1 mole of Cu.

Since the molarity of CuSO_4 is 0.05M in 1L:
\[ n_{\text{CuSO}_4} = 0.05 \, \text{mol/L} \times 1 \, \text{L} = 0.05 \, \text{mol} \]

The same number of moles of Mg (0.05 mol) will react with the CuSO_4.

The mass of Mg that reacted is:
\[ m_{\text{Mg reacted}} = n_{\text{Mg}} \times \text{molar mass of Mg} = 0.05 \, \text{mol} \times 24 \, \text{g/mol} = 1.2 \, \text{g} \]

If the mass increase (which is the mass of Cu deposited) is 0.0625m, we need to equate this to the mass of Cu deposited:
\[ 0.0625m = \text{mass of Cu deposited} \]

The moles of Cu deposited should be equal to the moles of CuSO_4 reacted:
\[ n_{\text{Cu}} = 0.05 \, \text{mol} \]

Mass of Cu deposited:
\[ \text{mass of Cu deposited} = n_{\text{Cu}} \times \text{molar mass of Cu} = 0.05 \, \text{mol} \times 64 \, \text{g/mol} = 3.2 \, \text{g} \]

Therefore:
\[ 0.0625m = 3.2 \, \text{g} \]

Solving for \( m \):
\[ m = \frac{3.2 \, \text{g}}{0.0625} = 51.2 \, \text{g} \]

### Mass of \( \text{Mg} \) that did not react

Initial mass of \( \text{Mg} \):
\[ m_{\text{initial}} = 51.2 \, \text{g} \]

Mass of \( \text{Mg} \) that reacted:
\[ m_{\text{Mg reacted}} = 1.2 \, \text{g} \]

Mass of \( \text{Mg} \) that did not react:
\[ m_{\text{Mg not reacted}} = m_{\text{initial}} - m_{\text{Mg reacted}} = 51.2 \, \text{g} - 1.2 \, \text{g} = 50.0 \, \text{g} \]

### Summary:
**Part A:**
The initial mass of the \( \text{Mg} \) strip is 51.2 g.

**Part B:**
The mass of \( \text{Mg} \) that did not react is 50.0 g.

Do you want details or have any questions?

Here are some additional questions related to this problem:

1. What is the molar mass of CuSO4?
2. How many moles of CuSO4 are there in a 0.05M solution of 1L?
3. What is the stoichiometric ratio between Mg and CuSO4 in the reaction?
4. How do you calculate the moles of a substance from its mass and molar mass?
5. What is the significance of the mass increase of the Mg strip in this reaction?
6. How can you verify the mass of Mg that did not react experimentally?
7. What are the possible sources of error in this type of experiment?
8. How would the results differ if the concentration of CuSO4 were different?

**Tip:** Always make sure to balance chemical equations before using them for stoichiometric calculations.

Learn how to calculate the initial mass of Mg and the mass of Mg that did not react in a CuSO4 solution reaction. This problem involves stoichiometry, molar mass calculations, and chemical reactions. Suitable for advanced high school chemistry students.

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