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The text from your uploaded image appears to be a math problem, stated in French. It asks:

"If 250 pins cost 500,000 FC, how much would be the total cost of 20% more pins?"

To solve this, let's first calculate how many pins constitute 20% more than 250:

20% of 250 pins = 0.20 × 250 = 50 pins.

So, 20% more than 250 pins is 250 + 50 = 300 pins.

Next, we'll calculate the cost of these 300 pins. If 250 pins cost 500,000 FC, the cost per pin is:

Cost per pin = 500,000 FC / 250 = 2,000 FC per pin.

Therefore, the total cost for 300 pins would be:

Total cost = 300 pins × 2,000 FC per pin = 600,000 FC.

So, 300 pins would cost 600,000 FC.

Would you like more details or have another question on this topic? Here are a few more questions you might consider:
1. What would be the cost if the number of pins increased by 30%?
2. How much would it cost to buy half as many pins?
3. Can you calculate the cost per pin if the total price changes but the number of pins stays the same?
4. What if the price per pin decreases by 10%, how would that affect the total cost for 250 pins?
5. How would you calculate the price increase if the cost per pin goes up by 15%?

**Tip:** When working with percentages, it’s often useful to convert the percentage to a decimal by dividing by 100 to simplify multiplication.

250 pains coûtent ensemble 500.000 FC. Si on réduit le nombre de pains de 20%, combien coûteront le reste de pains?

Learn how to calculate the new cost of 250 pains after reducing the quantity by 20%. This problem involves percentage decreases, unit rates, and basic arithmetic, making it suitable for students in Grades 6-8.

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