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What is the corner frequency of this circuit in Hz?

The circuit depicted in the second image is also an RC low-pass filter, but it includes two resistors \( R1 \) and \( R2 \). To find the corner frequency of this filter, we need to consider the equivalent resistance seen by the capacitor \( C1 \).

The equivalent resistance \( R_{eq} \) in this case is given by the parallel combination of \( R1 \) and \( R2 \):

\[ R_{eq} = \frac{R1 \cdot R2}{R1 + R2} \]

Once we have the equivalent resistance, we can calculate the corner frequency \( f_c \) using the same formula:

\[ f_c = \frac{1}{2 \pi R_{eq} C1} \]

To proceed with the calculation, please provide the values of \( R1 \), \( R2 \), and \( C1 \).

Would you like any additional details or have any questions? Here are five questions you might consider asking:

1. How do I calculate the equivalent resistance for other resistor configurations?
2. Can you explain the impact of each component on the filter's performance?
3. How can I measure the actual corner frequency of a physical circuit?
4. What are some practical considerations when selecting resistor and capacitor values?
5. How does loading effect influence the behavior of an RC filter?

**Tip:** When analyzing circuits with multiple resistors and capacitors, always check if resistors are in series or parallel to correctly calculate the equivalent resistance or capacitance.

Learn how to calculate the corner frequency of an RC low-pass filter with two resistors, R1 and R2, and capacitor C1. Understand the formula for equivalent resistance in parallel configurations and how it affects the filter's performance. Suitable for advanced learners and engineers.

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