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The problem asks to find the total area under the curve of \( f(x) = \cos(x) \) over the intervals \( \left[0, \frac{\pi}{2}\right] \) and \( \left[ \frac{3\pi}{2}, \frac{5\pi}{2} \right] \).

### To solve this:

1. **Area Calculation**:
   - The area under the curve of a function is given by the integral of that function over the given interval. Since we are asked for the total area, and we have two separate intervals, the area will be the sum of the integrals over each of these intervals.
   - The total area will be calculated as follows:
   
     \[
     A = \int_0^{\frac{\pi}{2}} \cos(x) \, dx + \int_{\frac{3\pi}{2}}^{\frac{5\pi}{2}} \cos(x) \, dx
     \]

2. **Correct

¿Cuál es el planteamiento para encontrar el área total bajo la curva de f(x) = cos(x) en los intervalos [0, π/2] y [3π/2, 5π/2]?

This problem involves calculating the total area under the curve of f(x) = cos(x) over the intervals [0, π/2] and [3π/2, 5π/2]. Learn how to set up and solve this integral using the fundamental theorem of calculus and trigonometric identities.

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