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To solve the problem, we are tasked with finding the total area under the curve \( f(x) = \cos(x) \) over two intervals: \([0, \frac{\pi}{2}]\) and \([\frac{3\pi}{2}, \frac{5\pi}{2}]\).

To calculate the area under a curve, we need to compute the definite integrals of the function over these intervals.

1. **Interval 1: \( [0, \frac{\pi}{2}] \)**
   The integral of \( \cos(x) \) over this interval gives us the area between 0 and \( \frac{\pi}{2} \).

2. **

¿Cuál es el planteamiento para encontrar el área total bajo la curva de f(x) = cos(x) en los intervalos [0, π/2] y [3π/2, 5π/2]?

Learn how to calculate the total area under the curve f(x) = cos(x) over the intervals [0, π/2] and [3π/2, 5π/2]. This problem involves definite integrals and trigonometric functions, using the Fundamental Theorem of Calculus. Suitable for high school students in Grades 11-12.

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