Given the equation \( 2^y = 2 \), we want to find the value of \( y \).

Since \( 2^y = 2 \), we can rewrite the right side of the equation as \( 2^1 \). This gives us:

\[
2^y = 2^1
\]

When the bases are the same, we can set the exponents equal to each other:

\[
y = 1
\]

So, the solution is \( y = 1 \).

Would you like more details, or do you have any questions?

Here are five related questions:
1. What is the solution for \( 3^x = 3^5 \)?
2. How do you solve the equation \( 2^x = 8 \)?
3. What happens if the base is different in \( a^x = b \)?
4. Can \( y = 1 \) be a solution for the equation \( 5^y = 2^5 \)?
5. How do you solve an equation involving logarithms, like \( \log(2^x) = 3 \)?

**Tip:** When working with exponential equations, if the bases on both sides of the equation are the same, you can directly equate the exponents to solve for the variable.

Learn how to solve the exponential equation 2^y = 2 with a detailed step-by-step solution. This problem covers the concept of exponential equations and how to solve them by equating exponents. Suitable for students in Grades 7-9.

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