Math Problem Statement
La altura de un objeto que se lanza hacia arriba, después de t segundos, es h=h0+v0t-4.9t2, donde h0 es la altura desde donde se lanza y v0 la velocidad con que se lanza. Si un objeto se lanza desde un techo a 7m de altura, a una velocidad de 15 m/s, ¿cuál sería su altura tres segundos después?
Solution
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Math Problem Analysis
Mathematical Concepts
Kinematics
Projectile Motion
Formulas
Equation of motion: h = h0 + v0t - 4.9t^2
Theorems
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Suitable Grade Level
High School
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