a car uses 45litres of fuel to travel 495km. how far can the car travel on 50litres of fuel at the same rate. how much fuel will the car use to travel 190km at the same rate.

To solve these problems, we will use the concept of direct proportionality since the car's fuel consumption rate is constant.

1. **Determine the car's fuel consumption rate:**

   The car uses 45 liters of fuel to travel 495 km.

   \[
   \text{Fuel consumption rate} = \frac{\text{Distance traveled}}{\text{Fuel used}} = \frac{495 \text{ km}}{45 \text{ liters}} = 11 \text{ km per liter}
   \]

2. **Calculate the distance the car can travel on 50 liters of fuel:**

   Using the fuel consumption rate:
   
   \[
   \text{Distance} = \text{Fuel consumption rate} \times \text{Fuel available} = 11 \text{ km/liter} \times 50 \text{ liters} = 550 \text{ km}
   \]

   Therefore, the car can travel 550 km on 50 liters of fuel.

3. **Calculate the fuel required to travel 190 km:**

   Using the fuel consumption rate:
   
   \[
   \text{Fuel required} = \frac{\text{Distance to travel}}{\text{Fuel consumption rate}} = \frac{190 \text{ km}}{11 \text{ km/liter}} \approx 17.27 \text{ liters}
   \]

   Therefore, the car will use approximately 17.27 liters of fuel to travel 190 km.

If you have any questions or need further details, feel free to ask.

Here are 5 more questions you might be interested in:

1. How do you convert fuel consumption from km per liter to miles per gallon?
2. What is the formula for calculating average speed?
3. How do you calculate the cost of a road trip given the fuel efficiency and fuel price?
4. What is the difference between direct and inverse proportionality in mathematics?
5. How do you solve problems involving compound interest in finance?

**Tip:** Always double-check units when performing calculations to avoid errors.

Learn how to calculate car fuel efficiency with this problem. Determine how far a car can travel on 50 liters of fuel and how much fuel it needs to travel 190 km at a constant rate. Detailed solutions and calculations provided.

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