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The image shows a rhomboid (parallelogram) with triangles \( RJU \) and \( HJT \), which are congruent. The question asks to calculate the angles \( \angle JHT \) and \( \angle JRU \), given the angles \( \angle RJU = 142^\circ \) and \( \angle HTJ = 21^\circ \).

### Solution:
1. Since triangles \( RJU \) and \( HJT \) are congruent, corresponding angles of these triangles are equal. This implies that:
   - \( \angle RJU = \angle HJT = 142^\circ \)
   - \( \angle HTJ = \angle JRU = 21^\circ \)

2. Using the fact that the angles in a triangle sum up to \( 180^\circ \), we can now calculate the remaining angle in triangle \( RJU \) or \( HJT \):
   \[
   \angle JUT = 180^\circ - 142^\circ - 21^\circ = 17^\circ
   \]
   Therefore, \( \angle JHT = 17^\circ \) and \( \angle JRU = 21^\circ \).

Thus, the correct answer is **Option A) 17° y 21°**.

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Would you like more details or have any questions? Here are 5 related questions for practice:
1. What are the criteria for two triangles to be congruent?
2. How do you calculate the third angle in a triangle when the other two are known?
3. What properties define a rhomboid?
4. Can two triangles be congruent if only one angle is given?
5. How do corresponding angles help in proving triangle congruence?

**Tip:** In a parallelogram, opposite angles are always equal, and the sum of consecutive angles is 180°.

Observa el romboide, donde los triángulos RJU y HJT son congruentes. Aplicando los criterios de congruencia de triángulos, calcula ¿cuánto miden los ángulos JHT y JRU, respectivamente?

Solve the problem involving congruent triangles RJU and HJT in a parallelogram. Learn how to calculate angles JHT and JRU using the sum of angles in a triangle. This problem involves key concepts like triangle congruence and properties of parallelograms, suitable for students in Grades 8-10.

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