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Let's go through the exercises from the file you uploaded.

### Exercise 1:
For a school trip, there are 20 chaperones and 298 students, making a total of \( 20 + 298 = 318 \) people. Each bus can carry 53 people. The student, Léo, thinks the buses will be perfectly full.

**Question: Are the buses perfectly full, and how many buses are needed?**

To find how many buses are required:
\[
\frac{318}{53} \approx 6.00
\]
This means that exactly 6 buses are needed, and they will indeed be full, as \( 6 \times 53 = 318 \). Léo is correct.

### Exercise 2:
1) a) **Find all divisors of 140 and 150:**
   - Divisors of 140: \( 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140 \)
   - Divisors of 150: \( 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150 \)

   b) **Find the common divisors of 140 and 150 (greater than 1):**
   - The common divisors are: \( 2, 5, 10 \).

2) Julien has 140 milk chocolates and 150 dark chocolates. He wants to make identical sets with no leftover chocolates. Using the common divisors from part 1b, we can determine how many sets (ballotins) he can make and the composition of each.

- **First possibility (2 sets):**
  - \( \frac{140}{2} = 70 \) milk chocolates and \( \frac{150}{2} = 75 \) dark chocolates per set.

- **Second possibility (5 sets):**
  - \( \frac{140}{5} = 28 \) milk chocolates and \( \frac{150}{5} = 30 \) dark chocolates per set.

- **Third possibility (10 sets):**
  - \( \frac{140}{10} = 14 \) milk chocolates and \( \frac{150}{10} = 15 \) dark chocolates per set.

Would you like further details or have any questions?

Here are 5 related questions to expand your knowledge:
1. How do you calculate the greatest common divisor (GCD) of two numbers?
2. Can the least common multiple (LCM) be useful in packaging problems like Julien's?
3. What is the best method for finding divisors of a large number?
4. How can you tell if two numbers are relatively prime?
5. In practical situations, how is rounding handled when people don't fit perfectly into available space?

**Tip:** When dealing with large groups, always round up for safety when calculating the number of buses or containers needed.

For a school trip, there are 20 chaperones and 298 students, making a total of 318 people. Each bus can carry 53 people. Léo thinks the buses will be perfectly full. Are the buses perfectly full, and how many buses are needed?

Solve the bus allocation problem for a school trip with 318 people, where each bus holds 53 passengers. Learn how division helps in calculating the number of buses and check if they will be perfectly full. Suitable for Grade 8-9 students.

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