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The problem asks to rotate the given polygon 90 degrees counterclockwise around the origin. To perform this transformation, we apply the following rotation rule for each vertex:

For a point \((x, y)\), the 90° counterclockwise rotation about the origin transforms it to \((-y, x)\).

Let's apply this to each vertex of the polygon:
1. **Point A**: \((-6, 4)\) → \((-4, -6)\)
2. **Point B**: \((2, 4)\) → \((-4, 2)\)
3. **Point C**: \((2, 0)\) → \((0, 2)\)
4. **Point D**: \((-2, 0)\) → \((0, -2)\)
5. **Point E**: \((0, 2)\) → \((-2, 0)\)
6. **Point F**: \((-6, 2)\) → \((-2, -6)\)

Now, the rotated polygon has the following vertices:
- A' = (-4, -6)
- B' = (-4, 2)
- C' = (0, 2)
- D' = (0, -2)
- E' = (-2, 0)
- F' = (-2, -6)

Would you like to see a detailed step-by-step explanation of the rotation process or a drawing of the rotated polygon?

### Relative Questions:
1. What is the geometric significance of rotating shapes?
2. How does rotating by 180° differ from rotating by 90°?
3. Can this method be used to rotate points in three-dimensional space?
4. How does a clockwise rotation differ mathematically from a counterclockwise one?
5. How do you determine the center of rotation when it isn't the origin?

### Tip:
Always ensure to apply the correct transformation rules based on the direction of rotation and the degree of rotation for accuracy.

Rotacione 90° o polígono a seguir com relação à origem no sentido anti-horário.

Learn how to rotate a polygon 90 degrees counterclockwise around the origin on a coordinate plane. Apply the rotation formula (-y, x) for each vertex of the polygon. This problem covers geometry concepts suitable for students in Grades 8-10.

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