To solve the equation \( 3x - 1 = 2x + 8 \), we can follow these steps:

1. **Subtract \( 2x \) from both sides** to get all terms involving \( x \) on one side of the equation:

   \[
   3x - 2x - 1 = 8
   \]

   This simplifies to:

   \[
   x - 1 = 8
   \]

2. **Add 1 to both sides** to isolate \( x \):

   \[
   x - 1 + 1 = 8 + 1
   \]

   This simplifies to:

   \[
   x = 9
   \]

So, the solution to the equation is \( x = 9 \).

Would you like more details or have any questions about this solution?

Here are some related questions you might find helpful:

1. How do you solve equations with variables on both sides?
2. What are the properties of equality used in solving linear equations?
3. How can you check if the solution to an equation is correct?
4. What are the steps to isolate a variable in a linear equation?
5. How do you solve equations that involve fractions or decimals?

**Tip:** Always check your solution by substituting it back into the original equation to verify that both sides are equal.

Learn how to solve the linear equation 3x - 1 = 2x + 8 with a detailed step-by-step solution. This problem covers key algebraic concepts, including solving equations with variables on both sides. Suitable for students in Grades 7-9.

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