(5.475m x4.00m)/ 7.38m = how many m  making sure that your answer has the correct number of significant figures:

To solve \(\frac{(5.475 \, \text{m} \times 4.00 \, \text{m})}{7.38 \, \text{m}}\) and ensure the answer has the correct number of significant figures, follow these steps:

### Step 1: Multiply the numerator values
\[
5.475 \, \text{m} \times 4.00 \, \text{m} = 21.900 \, \text{m}^2
\]

- **Significant Figures:** 5.475 has 4 significant figures, and 4.00 has 3 significant figures, so the product should have 3 significant figures.

\[
21.900 \, \text{m}^2 \text{ (keeping 3 significant figures, it's rounded to 21.9 m}^2\text{)}
\]

### Step 2: Divide by the denominator
\[
\frac{21.9 \, \text{m}^2}{7.38 \, \text{m}} = 2.9661 \, \text{m}
\]

- **Significant Figures:** 21.9 has 3 significant figures, and 7.38 has 3 significant figures, so the quotient should be rounded to 3 significant figures.

### Step 3: Round to 3 significant figures
\[
2.9661 \, \text{m} \approx 2.97 \, \text{m}
\]

### Final Answer
\[
\boxed{2.97 \, \text{m}}
\]

This is the final answer with the correct number of significant figures.

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Would you like further explanation on any step?

Here are 5 related questions:
1. What rules govern the number of significant figures in addition and subtraction?
2. How do significant figures affect the precision of measurements?
3. What is the difference between precision and accuracy in measurements?
4. Can you explain the significance of exact numbers in significant figures?
5. How would the answer change if the numbers were expressed in scientific notation?

**Tip:** Always perform the rounding in the final step to avoid losing precision during intermediate calculations.

Learn how to solve a math problem involving significant figures. Find out how to correctly apply significant figures in calculations with a detailed step-by-step solution. Suitable for Grades 9-12.

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