9x^2 + 5= -2x Fill in a, b, and c.
a should be positive.
a, b, and c should be reduced

To solve the equation \(9x^2 + 5 = -2x\), let's first bring all the terms to one side of the equation to get it into the standard form \(ax^2 + bx + c = 0\).

Starting with:
\[
9x^2 + 5 = -2x
\]

Add \(2x\) to both sides to get:
\[
9x^2 + 2x + 5 = 0
\]

Now, the equation is in the standard form \(ax^2 + bx + c = 0\), where:

- \(a = 9\)
- \(b = 2\)
- \(c = 5\)

Since \(a\) is positive, and the coefficients are already in their simplest form, the values are:

- \(a = 9\)
- \(b = 2\)
- \(c = 5\)

Would you like more details or have any questions? Here are five related questions to consider:

1. How can you solve this quadratic equation using the quadratic formula?
2. What methods can you use to determine the nature of the roots for this equation?
3. How would you approach graphing this quadratic equation?
4. What are the possible solutions when factoring a quadratic equation?
5. How do the values of \(a\), \(b\), and \(c\) affect the shape and position of the parabola?

**Tip:** Always double-check that the coefficients are in their simplest form and ensure the equation is set to \(0\) before identifying \(a\), \(b\), and \(c\).

Learn how to solve the quadratic equation 9x^2 + 2x + 5 with a detailed step-by-step solution. This problem covers key algebraic concepts, including the quadratic equation formula and the quadratic formula theorem. Suitable for students in Grades 9-12.

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