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The expression given is \( \log_3 9 \), which represents the logarithm of 9 with base 3. To solve this:

We want to find the exponent to which 3 must be raised to result in 9. Mathematically, this can be written as:

\[
3^x = 9
\]

Since \( 9 = 3^2 \), we can rewrite the equation as:

\[
3^x = 3^2
\]

Thus, \( x = 2 \).

Therefore, \( \log_3 9 = 2 \).

Would you like any additional details or clarifications? Here are five related questions for further exploration:

1. What is \( \log_3 27 \)?
2. How do you solve logarithmic equations with different bases?
3. Can you express \( \log_b (xy) \) using logarithmic properties?
4. What is the relationship between logarithms and exponents?
5. How can you solve for \( x \) in \( \log_5 (25x) = 3 \)?

**Tip:** Remember that \( \log_b a = x \) means \( b^x = a \). This is the key relationship between logarithms and exponents!

Learn how to solve log_3 9 by applying logarithmic properties. This problem involves understanding the relationship between logarithms and exponents, including the formula log_b a = x, which means b^x = a. Suitable for students in Grades 8-10.

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