The equation you've provided is:

\[ 3x + 5 = 0 \]

Let's solve it for \( x \):

1. Subtract 5 from both sides to isolate the term with \( x \):

   \[
   3x = -5
   \]

2. Divide both sides by 3 to solve for \( x \):

   \[
   x = \frac{-5}{3}
   \]

So, the solution is:

\[
x = -\frac{5}{3}
\]

Would you like more details on how this solution was reached or have any other questions? Here are some related questions you might find interesting:

1. How do you solve equations of the form \( ax + b = 0 \)?
2. What are some real-life applications of linear equations like \( 3x + 5 = 0 \)?
3. How do you check if a solution to a linear equation is correct?
4. What happens when the coefficient of \( x \) is 0 in an equation like this?
5. How do linear equations differ from quadratic equations?

**Tip:** Always check your solution by substituting it back into the original equation to ensure it satisfies the equation!

Learn how to solve the linear equation 3x + 5 = 0 with a detailed step-by-step solution. This problem covers key algebraic concepts, including linear equations and solving methods. Suitable for students in Grades 7-9.

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