The derivative of \( 4\pi^2 \) with respect to any variable is 0, because \( 4\pi^2 \) is a constant (since \( \pi \) is a constant, approximately equal to 3.14159). 

Therefore, 
\[
(4\pi^2)' = 0
\]

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Here are 5 related questions to explore:

1. What is the derivative of \( \pi^2 x \) with respect to \( x \)?
2. How do you differentiate \( \sin(\pi x) \)?
3. What is the derivative of \( 4\pi^2 x^2 \)?
4. How would you compute the second derivative of a constant function?
5. What happens when differentiating a constant multiplied by a function?

**Tip:** The derivative of a constant is always zero because constants do not change, hence their rate of change (slope) is zero.

Explore the derivative of the constant 4π^2 in this detailed solution. Learn why the derivative of any constant, such as 4π^2, is always zero due to its unchanging nature. This topic is a fundamental part of calculus, especially in differentiation. Suitable for students in Grades 11-12.

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