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Let's break down the problem and solve it step-by-step.

### Given Data:
1. Mass of \( 1 \, \text{cm}^3 \) of copper: \( 9 \, \text{g} \)
2. Mass of one copper atom: \( 10^{-22} \, \text{g} \)
3. Diameter of one copper atom: \( 10^{-10} \, \text{m} \)

### Question:
If we form a chain by placing all the atoms contained in \( 1 \, \text{cm}^3 \) of copper side by side, would it be long enough to encircle the Earth?

### Step-by-Step Solution:

1. **Calculate the number of atoms in \( 1 \, \text{cm}^3 \) of copper:**

   \[
   \text{Number of atoms} = \frac{\text{Total mass}}{\text{Mass of one atom}} = \frac{9 \, \text{g}}{10^{-22} \, \text{g}}
   \]

   \[
   \text{Number of atoms} = 9 \times 10^{22}
   \]

2. **Calculate the total length of the chain:**

   Since the diameter of one atom is \( 10^{-10} \, \text{m} \), placing \( 9 \times 10^{22} \) atoms side by side:

   \[
   \text{Total length} = (\text{Number of atoms}) \times (\text{Diameter of one atom})
   \]

   \[
   \text{Total length} = 9 \times 10^{22} \times 10^{-10} \, \text{m}
   \]

   \[
   \text{Total length} = 9 \times 10^{12} \, \text{m}
   \]

3. **Compare with the circumference of the Earth:**

   The Earth's circumference is approximately \( 40,000 \, \text{km} \) or \( 4 \times 10^7 \, \text{m} \).

   \[
   \frac{\text{Total length of the chain}}{\text{Earth's circumference}} = \frac{9 \times 10^{12} \, \text{m}}{4 \times 10^7 \, \text{m}}
   \]

   \[
   = 2.25 \times 10^5
   \]

   This means the chain would wrap around the Earth \( 225,000 \) times.

### Conclusion:
Yes, the chain formed by all the atoms in \( 1 \, \text{cm}^3 \) of copper would be more than sufficient to encircle the Earth.

---

Would you like a more detailed explanation of any part? Here are five related questions you might find interesting:

1. How would the result change if the density of the material were different?
2. What is the significance of atomic size in the properties of materials?
3. How does the atomic mass unit relate to the actual mass of atoms?
4. What other factors could affect the practical formation of such a chain?
5. How does the arrangement of atoms in a solid differ from the arrangement in a chain?

**Tip:** Understanding the relationship between atomic properties and macroscopic measurements helps in grasping concepts in materials science and physics.

La masse de 1 cm³ de cuivre est 9 g. Celle d’un atome de ce même métal est 10^-22 g. Le diamètre d’un atome est 10^-10 m. Si l’on formait une chaîne en disposant côte à côte tous les atomes contenus dans 1 cm³ de cuivre, serait-elle suffisamment longue pour faire le tour de la Terre ?

Solve a fascinating problem involving atomic mass and linear measurement. Calculate how many times a chain of copper atoms from 1 cm³ of copper can wrap around the Earth. Key concepts include atomic mass, proportions, and geometry. Suitable for high school students.

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