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The problem asks to find the approximate mass of the Earth in pounds given the mass in grams and the conversion factor between grams and pounds.

We are given:

- The mass of the Earth in grams: \( 6.1 \times 10^{27} \text{ grams} \).
- The conversion factor from grams to pounds: \( 1 \text{ gram} = 2.2 \times 10^{-3} \text{ pounds} \).

To find the mass in pounds, we multiply the Earth's mass by the conversion factor:

\[
\text{Mass in pounds} = 6.1 \times 10^{27} \text{ grams} \times 2.2 \times 10^{-3} \text{ pounds/gram}
\]

First, calculate the numerical part:

\[
6.1 \times 2.2 = 13.42
\]

Now handle the powers of 10:

\[
10^{27} \times 10^{-3} = 10^{24}
\]

So, the mass of the Earth in pounds is approximately:

\[
1.342 \times 10^{25} \text{ pounds}
\]

Thus, the correct answer is **C: \( 1.342 \times 10^{25} \)**.

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Do you have any questions or would you like further details on this calculation?

Here are 5 related questions you can explore:
1. How do you multiply numbers in scientific notation?
2. What are the benefits of using scientific notation in real-world problems?
3. How would you convert pounds back to grams using the inverse of the conversion factor?
4. How does the Earth's mass compare to other celestial bodies?
5. Why is scientific notation useful for very large or very small numbers?

**Tip:** When multiplying numbers in scientific notation, always handle the numerical parts and powers of 10 separately for clarity.

Si la masa de la tierra es de aproximadamente 6.1 × 10^27 gramos y cada gramo equivale a 2.2 × 10^−3 libras, ¿cuál es la masa de la tierra en libras aproximadamente?

Learn how to convert the mass of the Earth from grams to pounds using scientific notation. This problem involves multiplying large numbers with exponents and applying unit conversion techniques. Suitable for high school students, the solution walks through step-by-step calculations with a final answer of approximately 1.342 × 10^25 pounds.

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