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The problem describes the relationship between the volume, temperature, and pressure of a gas, suggesting that it follows the **ideal gas law**:

\[
PV = nRT
\]

Or in its simplified form when comparing two states of a gas:

\[
\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
\]

Where:
- \(P_1\), \(V_1\), and \(T_1\) represent the initial pressure, volume, and temperature.
- \(P_2\), \(V_2\), and \(T_2\) represent the final pressure, volume, and temperature.

### Given:
- Initial temperature \(T_1 = 300 \, K\)
- Initial pressure \(P_1 = 3 \, \text{atm}\)
- Initial volume \(V_1 = 2 \, \text{liters}\)
- Final temperature decrease: \(T_2 = 300 \, K - 100 \, K = 200 \, K\)
- Final pressure increase: \(P_2 = 3 \, \text{atm} + 1 \, \text{atm} = 4 \, \text{atm}\)
  
### Find:
- Final volume \(V_2\).

Let me calculate the final volume using the equation above.The final volume of the gas, after the temperature decreases by 100 K and the pressure increases by 1 atm, will be **1 liter**.

Do you want further details or have any questions? Here are five related questions for practice:

1. How does temperature affect the volume of a gas when the pressure is kept constant?
2. What would happen to the volume if both temperature and pressure were doubled?
3. Can you explain the relationship between pressure and volume according to Boyle's Law?
4. What would the final volume be if the pressure stayed the same but the temperature dropped by 150 K?
5. How would the result change if the gas used was not ideal?

**Tip:** Always make sure to use absolute temperatures (Kelvin) when applying the ideal gas law!

Sabiendo que el volumen que presenta un gas en un recipiente es DP a su temperatura e IP a la presión y cuando el recipiente presentó una temperatura de 300°K a una presión de 3 atm, contiene un volumen de 2 litros de gas metano. ¿Cuál será su volumen cuando la temperatura se reduzca en 100°K y su presión aumente 1 atm?

Learn how to calculate the volume change of a gas when its temperature decreases and its pressure increases using the ideal gas law. In this example, a gas initially at 300 K and 3 atm with a volume of 2 liters is evaluated after a 100 K drop in temperature and a 1 atm increase in pressure.

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