Solve for cc.
8, equals, minus, 3, c, plus, 29
8=
−3c+29' only whole number

We are given the equation:

\[
8 = -3c + 29
\]

### Solving for \( c \):

1. **Subtract 29 from both sides**:
   \[
   8 - 29 = -3c
   \]
   Simplifying the left side:
   \[
   -21 = -3c
   \]

2. **Divide both sides by -3**:
   \[
   c = \frac{-21}{-3}
   \]
   Simplifying the division:
   \[
   c = 7
   \]

### Solution:
The value of \( c \) is \( 7 \).

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Would you like further details on any step? Here are some related questions you could explore:

1. What happens if the equation had a decimal instead of a whole number?
2. How would you solve the equation if \( c \) was on both sides?
3. What if the equation was multiplied by a factor? How would that change the approach?
4. How can you check if your solution for \( c \) is correct?
5. How would this equation look if it was written as a function of \( c \)?
6. What if instead of subtraction, it had addition—how would that change things?
7. How would you graph this equation?
8. What if \( c \) was part of an inequality instead of an equation?

**Tip:** Always double-check your solution by plugging the value of the variable back into the original equation.

Learn how to solve the equation 8 equals minus 3c plus 29 for the variable c with a step-by-step solution. This problem involves solving linear equations and understanding basic algebraic operations. Suitable for Grades 7-9.

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