Let's solve the equation \( 5(2z + 8) = 50 \).

1. **Distribute the 5** to both terms inside the parentheses:
   \[
   5 \times 2z + 5 \times 8 = 50
   \]
   \[
   10z + 40 = 50
   \]

2. **Subtract 40** from both sides to isolate the term with \( z \):
   \[
   10z = 50 - 40
   \]
   \[
   10z = 10
   \]

3. **Divide both sides by 10** to solve for \( z \):
   \[
   z = \frac{10}{10}
   \]
   \[
   z = 1
   \]

So, the solution is \( z = 1 \).

Would you like more details or have any questions?

Here are 5 related questions you might find useful:
1. How would you solve \( 3(4x + 5) = 27 \)?
2. What is the solution to \( 7(2y - 3) = 28 \)?
3. How can you solve \( 6(3a + 7) = 60 \)?
4. What is the next step if \( 4(5x - 2) = 36 \)?
5. How would you solve \( 8(2b + 1) = 64 \)?

**Tip:** Always remember to distribute multiplication over addition or subtraction when working with parentheses in an equation.

Learn how to solve the equation 5(2z + 8) = 50 with a detailed step-by-step solution. This problem covers key algebraic concepts, including equations and the distributive property. Suitable for students in Grades 6-8.

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