A box is filled with several party favours. It contains 12 hats, 15 noisemakers, ten finger traps, and five bags of confetti.

Let N = the event of getting a noisemaker.

Find P(N) to two decimal places.

To find the probability of getting a noisemaker, \( P(N) \), we need to divide the number of noisemakers by the total number of party favors.

### Step 1: Total number of party favors
The total number of party favors is the sum of all the items in the box:
\[
12 \, (\text{hats}) + 15 \, (\text{noisemakers}) + 10 \, (\text{finger traps}) + 5 \, (\text{bags of confetti}) = 42
\]

### Step 2: Probability of getting a noisemaker
The probability is calculated as:
\[
P(N) = \frac{\text{Number of noisemakers}}{\text{Total number of party favors}} = \frac{15}{42}
\]

Simplifying:
\[
P(N) = \frac{5}{14} \approx 0.36
\]

Thus, the probability \( P(N) \) is approximately **0.36** to two decimal places.

Would you like further details or have any questions?

Here are five related questions:
1. What is the probability of picking a hat?
2. What is the probability of picking either a noisemaker or a hat?
3. How would the probability change if three noisemakers were removed?
4. What is the probability of not picking a noisemaker?
5. What is the probability of picking a finger trap?

**Tip:** When calculating probabilities, always ensure the total number of possible outcomes is correctly counted!

A box is filled with several party favours. It contains 12 hats, 15 noisemakers, ten finger traps, and five bags of confetti. Let N = the event of getting a noisemaker. Find P(N) to two decimal places.

Learn how to calculate the probability of picking a noisemaker from a box filled with party favors, including 12 hats, 15 noisemakers, 10 finger traps, and 5 bags of confetti. The problem explores basic probability concepts and applies the formula for determining the probability of an event. Suitable for Grades 6-8.

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