Math Problem Statement
已知f(x)=x-sinx,当x>=0时,f(x)<=ax²,求a的取值范围
Solution
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Math Problem Analysis
Mathematical Concepts
Calculus
Inequalities
Limit Analysis
Formulas
f(x) = x - \sin x
f'(x) = 1 - \cos x
Limit: \lim_{x \to 0^+} f(x) \approx \frac{x^3}{6}
Quadratic inequality: f(x) \leq ax^2
Theorems
Monotonicity of functions
Limit behavior analysis
Suitable Grade Level
Grades 11-12, University Level
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