A survey of Mr. Thorne’s class shows that 5 out of 8 students will buy lunch today. Based on this result, how many of the 720 students in the school will buy today? Use any strategy to solve.

 

To solve this problem, we can use the concept of **ratios and proportions**. Here's how:

1. According to the survey, **5 out of 8 students** in Mr. Thorne’s class will buy lunch today. 
2. This ratio can be written as:
   \[
   \frac{5}{8}
   \]
3. We need to find out how many students out of the total **720** in the school will buy lunch today. Let **x** represent the number of students who will buy lunch. So, we set up a proportion:
   \[
   \frac{5}{8} = \frac{x}{720}
   \]
4. To solve for **x**, we can cross-multiply:
   \[
   5 \times 720 = 8 \times x
   \]
   \[
   3600 = 8x
   \]
5. Now, divide both sides by 8:
   \[
   x = \frac{3600}{8} = 450
   \]

So, **450 students** out of 720 will buy lunch today, based on the survey.

Would you like more details on this method, or have any questions?

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Here are 5 related questions:
1. If 6 out of 9 students will buy lunch, how many students out of 720 will buy lunch?
2. What percentage of students in Mr. Thorne’s class are buying lunch today?
3. If 4 out of 10 students in a different class will buy lunch, how many students will buy lunch from that class of 30?
4. How would the result change if the survey showed that 7 out of 8 students will buy lunch?
5. Can you set up the proportion for a class where 3 out of 5 students buy lunch?

**Tip:** Proportions are a powerful way to solve problems when two quantities have the same relative relationship.

A survey of Mr. Thorne’s class shows that 5 out of 8 students will buy lunch today. Based on this result, how many of the 720 students in the school will buy today? Use any strategy to solve.

Find out how many students will buy lunch today using ratios and proportions. Based on a survey of Mr. Thorne's class, where 5 out of 8 students will buy lunch, this solution calculates that 450 out of 720 students in the school will also buy lunch. Perfect for students in Grades 6-8 learning about ratios and cross-multiplication.

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