To factorize the expression \(100 - 36x^2\), we again recognize that it is a difference of squares. The difference of squares formula is given by:

\[ x^2 - y^2 = (x - y)(x + y) \]

In this case, \(100\) and \(36x^2\) are both perfect squares:
- \(100 = 10^2\)
- \(36x^2 = (6x)^2\)

So, we can rewrite the expression as:

\[ 100 - 36x^2 = 10^2 - (6x)^2 \]

Applying the difference of squares formula:

\[ 10^2 - (6x)^2 = (10 - 6x)(10 + 6x) \]

Therefore, the factorized form of \(100 - 36x^2\) is:

\[ 100 - 36x^2 = (10 - 6x)(10 + 6x) \]

Would you like more details or have any questions?

Here are 8 related questions for further exploration:
1. How do you factorize \(49 - 25y^2\)?
2. What is the factored form of \(81 - 16z^2\)?
3. Can you factorize \(64a^2 - 1\)?
4. How do you recognize and factorize perfect square trinomials?
5. What is the factored form of \(144 - 49b^2\)?
6. How do you solve \(100 - 36x^2 = 0\)?
7. What happens if you have a sum of squares, such as \(100 + 36x^2\)?
8. How can the difference of squares method be applied to factorize higher degree polynomials?

**Tip:** When dealing with polynomials, always check if they can be expressed as a difference of squares, sum or difference of cubes, or other recognizable patterns to simplify the factorization process.

Learn how to factorize the expression 100 - 36x^2 using the difference of squares formula. Detailed step-by-step solution and explanation provided. Suitable for high school students studying algebra and polynomials.

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