Math Problem Statement
Find the equation of a line perpendicular toy, plus, 5, equals, start fraction, 3, divided by, 2, end fraction, xy+5= 2 3 xthat passes through the point left parenthesis, 3, comma, 4, right parenthesis(3,4). Answer Multiple Choice Answers y, equals, start fraction, 3, divided by, 2, end fraction, x, plus, 5y= 2 3 x+5 y, equals, start fraction, 2, divided by, 3, end fraction, x, plus, 6y= 3 2 x+6 y, equals, minus, start fraction, 3, divided by, 2, end fraction, x, plus, 5y=− 2 3 x+5 y, equals, minus, start fraction, 2, divided by, 3, end fraction, x, plus, 6y=− 3 2 x+6
Solution
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
Slopes of Perpendicular Lines
Point-Slope Form
Formulas
Slope-intercept form: y = mx + b
Point-slope form: y - y1 = m(x - x1)
Perpendicular slopes: m1 * m2 = -1
Theorems
Slopes of Perpendicular Lines
Suitable Grade Level
Grades 9-12
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