Math Problem Statement
El Iodato de una muestra de 20,00 mL de una solución acuosa de NaIO2, se reduce cuantitativamente a I- y se titula con AgNO3 0,1016 N gastando 23,15 mL. Calcular el contendo de iodato de sodio en g/L. Datos: Mr yodo: 126,905 Mr Oxigeno= 15,999 y Mr sodio= 22,990
Solution
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Math Problem Analysis
Mathematical Concepts
Stoichiometry
Titration
Molar Mass Calculation
Normality in Chemistry
Formulas
Equivalentes de AgNO₃ = Volumen (L) × Normalidad (N)
Moles = Equivalentes de AgNO₃
Masa molar de NaIO₂ = Mr Na + Mr I + 2 × Mr O
Masa de NaIO₂ = Moles × Masa Molar
Concentración (g/L) = Masa (g) / Volumen (L)
Theorems
Stoichiometry of Titration Reactions
Molar Mass Calculation
Concentration Conversion (g/L)
Suitable Grade Level
Undergraduate Chemistry
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