Math Problem Statement
Unos trabajadores están colocando materiales en un elevador de carga que se encuentra en un pique vertical, no se percatan y lo sobrecargan y el cable que se encontraba desgastado se corta. Al presentarse el accidente el elevador cargado es de 1400 kilogramos (kg). Al caer, los carriles guías ejercen una fuerza retardadora de 3500 Newton (N). Con qué rapidez chocará el elevador contra el fondo del pique, 70 metros abajo.
Solution
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Math Problem Analysis
Mathematical Concepts
Kinematics
Forces and Motion
Energy
Formulas
Net Force (F_n) = Weight (P) - Retarding Force (F_r)
Weight (P) = mass (m) * gravity (g)
Newton's Second Law: F = m * a
Kinematic equation: v_f^2 = v_i^2 + 2 * a * h
Theorems
Newton's Second Law of Motion
Suitable Grade Level
High School (Grades 10-12)
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