How long would it take an object to fall to the ground from the top of the Leaning Tower of Pisa (height = 54.6m)?



To calculate the time it takes for an object to fall from the top of the Leaning Tower of Pisa, we'll use the basic equation of motion under gravity:

\[
h = \frac{1}{2} g t^2
\]

Where:
- \( h \) is the height (54.6 meters),
- \( g \) is the acceleration due to gravity (approximately 9.8 m/s²),
- \( t \) is the time it takes to fall.

We solve for \( t \):

\[
t = \sqrt{\frac{2h}{g}}
\]

Now, let's calculate the time.

The time it would take for an object to fall from the top of the Leaning Tower of Pisa (54.6 meters) is approximately **3.34 seconds**.

Would you like more details or have any other questions?

Here are 5 related questions:
1. What would be the impact velocity of the object when it hits the ground?
2. How would the time change if the tower were twice as tall?
3. What if we consider air resistance? How would that affect the fall time?
4. How does the gravitational acceleration vary on different planets?
5. How long would it take for a feather to fall from the same height (ignoring air resistance)?

**Tip:** Always consider whether air resistance is negligible or not when calculating real-world fall times.

Discover how long it takes for an object to fall from the top of the Leaning Tower of Pisa (height = 54.6 meters). Use the equation of motion under gravity and calculate the fall time with detailed steps. Suitable for high school students studying physics.

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