Math Problem Statement
Qual integral dá o comprimento do arco da equação \[y=\dfrac{1}x\] do ponto \[\left(\dfrac{1}{2},2\right)\] até o ponto \[\left(2,\dfrac{1}2\right)\]? Escolha 1 resposta: Escolha 1 resposta: (Escolha A) \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}x}\,dx\] A \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}x}\,dx\] (Escolha B) \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}{x^2}}\,dx\] B \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}{x^2}}\,dx\] (Escolha C) \[\displaystyle \int_{1/2}^2 \sqrt{1-\dfrac{1}{x^2}}\,dx\] C \[\displaystyle \int_{1/2}^2 \sqrt{1-\dfrac{1}{x^2}}\,dx\] (Escolha D) \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}{x^4}}\,dx\] D \[\displaystyle \int_{1/2}^2 \sqrt{1+\dfrac{1}{x^4}}\,dx\]
Solution
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Math Problem Analysis
Mathematical Concepts
Calculus
Integration
Arc Length
Formulas
Arc length formula: L = \int_a^b \sqrt{1 + (\frac{dy}{dx})^2}\, dx
Theorems
-
Suitable Grade Level
Advanced High School
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