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To solve this problem, we need to find the perimeter of the given polygon by summing the lengths of all its sides.

The figure has the following side lengths, based on the labels in the image:

- Bottom side = 12 cm
- Left vertical side = 5 cm
- Left diagonal side = 6 cm
- Short horizontal side = 4 cm
- Another diagonal side = 4 cm
- Top horizontal side = 5 cm
- Right vertical side = 8 cm
- Small horizontal side = 3 cm
- Short vertical side = 2 cm

Now, summing all the side lengths:

\[
\text{Perimeter} = 12 + 5 + 6 + 4 + 4 + 5 + 8 + 3 + 2
\]

Let me calculate that.The perimeter of the given figure is \( 49 \, \text{cm} \).

Let me know if you would like any further details or have any questions!

Here are some related questions you might find interesting:

1. How would the perimeter change if one of the sides increased by 2 cm?
2. What is the formula for the perimeter of other polygons, such as triangles or rectangles?
3. How can we calculate the area of this irregular figure?
4. What are some properties of polygons with different numbers of sides?
5. If the figure were scaled down by a factor of 2, what would the new perimeter be?

**Tip:** When finding the perimeter of any polygon, make sure all the side lengths are accounted for, especially if some sides aren't directly labeled!

Find the perimeter of the given figure (not drawn to scale).

Learn how to find the perimeter of an irregular polygon with side lengths of 12 cm, 5 cm, 6 cm, 4 cm, 4 cm, 5 cm, 8 cm, 3 cm, and 2 cm. This geometry problem explains the method for summing side lengths to calculate the perimeter of polygons. Suitable for Grades 5-7.

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