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The equation provided is:

\[
7x - 70 = 6x - 30
\]

### Step-by-Step Solution:

1. **Move all terms involving \(x\) to one side of the equation:**
   Subtract \(6x\) from both sides:

   \[
   7x - 6x - 70 = -30
   \]

   Simplifying this:

   \[
   x - 70 = -30
   \]

2. **Move the constant terms to the other side:**
   Add \(70\) to both sides:

   \[
   x = -30 + 70
   \]

   Simplifying this:

   \[
   x = 40
   \]

### Final Answer:
\[
x = 40
\]

Would you like more details or explanations on any step?

Here are 5 related questions you might find interesting:
1. How do we handle equations with variables on both sides?
2. What would happen if the equation had no solution?
3. Can you explain how to verify the solution \(x = 40\)?
4. What if the equation included fractions? How would the approach change?
5. What is the difference between solving linear and quadratic equations?

**Tip:** Always check your solution by substituting the value of \(x\) back into the original equation to verify its correctness.

Learn how to solve the linear equation 7x - 70 = 6x - 30 with a clear step-by-step solution. This problem focuses on essential algebraic techniques, including isolating the variable and balancing the equation. Suitable for students in Grades 6-8.

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