Let's solve the equation \(3x + 5 = 20\).

1. **Move the constant term** on the left side to the right side by subtracting 5 from both sides:
   \[
   3x + 5 - 5 = 20 - 5
   \]
   Simplifying this gives:
   \[
   3x = 15
   \]

2. **Isolate the variable \(x\)** by dividing both sides by 3:
   \[
   \frac{3x}{3} = \frac{15}{3}
   \]
   Simplifying this gives:
   \[
   x = 5
   \]

So, the solution is \(x = 5\).

Would you like any further details or have any questions?

Here are some related questions you might find interesting:

1. How would you solve the equation \(4x + 5 = 25\)?
2. What happens if the equation is \(3x + 5 = 30\) instead?
3. How do you solve an equation with a negative coefficient, such as \(-3x + 5 = 20\)?
4. What is the solution to the equation \(3x + 7 = 20\)?
5. How would the solution change if there was a different constant on the right side, like \(3x + 5 = 10\)?

**Tip:** When solving linear equations, always perform the same operation on both sides of the equation to maintain balance.

Learn how to solve the linear equation 3x + 5 = 20 with a detailed step-by-step solution. This problem covers key algebraic concepts, including solving linear equations and isolating variables. Suitable for students in Grades 7-9.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation