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The expression provided is:

\[
A = (6x + 1)(x + 2)
\]

To simplify this, we can apply the distributive property (also known as FOIL in binomial multiplication) to expand the expression:

\[
A = (6x + 1)(x + 2) = (6x \cdot x) + (6x \cdot 2) + (1 \cdot x) + (1 \cdot 2)
\]

Let's compute each term:

1. \(6x \cdot x = 6x^2\)
2. \(6x \cdot 2 = 12x\)
3. \(1 \cdot x = x\)
4. \(1 \cdot 2 = 2\)

Now, combine all these terms:

\[
A = 6x^2 + 12x + x + 2
\]

Simplify the like terms:

\[
A = 6x^2 + 13x + 2
\]

Thus, the simplified form of the expression is:

\[
A = 6x^2 + 13x + 2
\]

Would you like further details or have any questions?

Here are 5 related questions:
1. How can you factor a quadratic expression like \(6x^2 + 13x + 2\)?
2. What are the roots of the quadratic equation \(6x^2 + 13x + 2 = 0\)?
3. How does the distributive property (FOIL) work in binomial multiplication?
4. How can you graph a quadratic function like \(6x^2 + 13x + 2\)?
5. What is the vertex of the parabola represented by \(A = 6x^2 + 13x + 2\)?

**Tip:** When simplifying expressions, always combine like terms (terms with the same power of \(x\)) to ensure the result is in its simplest form.

A = (6x + 1)(x + 2). Simplify this expression.

Learn how to simplify the algebraic expression (6x + 1)(x + 2) using the distributive property. This problem covers binomial multiplication and quadratic equation basics. Suitable for students in Grades 8-10.

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