https://r2.erweima.ai/mathbot/image/1725850921610wkfkxs0h.jpg

The problem in the image reads:

"**PQ × QP = 273**, where P and Q represent 2 different digits. Find both 2-digit numbers, PQ and QP."

Let me walk through the steps to solve this:

1. Let **PQ** represent the two-digit number with digits P and Q, which means:
   \[
   PQ = 10P + Q
   \]
2. Similarly, **QP** represents the number where the digits are reversed, so:
   \[
   QP = 10Q + P
   \]
3. We are given that the product of these two numbers is 273:
   \[
   (10P + Q) \times (10Q + P) = 273
   \]

This results in the equation:
\[
(10P + Q)(10Q + P) = 273
\]
Expanding this, we get:
\[
100PQ + 10P^2 + 10Q^2 + PQ = 273
\]
Simplifying, we have:
\[
100PQ + P + Q = 273
\]
Soluble value.

PQ × QP = 273, where P and Q represent 2 different digits. Find both 2-digit numbers, PQ and QP.

Learn how to find two-digit numbers PQ and QP such that their product is 273. This problem involves number theory and algebraic concepts, suitable for students in Grades 5-7.

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