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**Question:**

You randomly draw a marble from a bag of marbles that contains 6 blue marbles, 4 green marbles, and 8 red marbles. What is the probability of drawing a blue or green marble?

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To solve this, let's go step by step:

1. **Total number of marbles** = \( 6 \, \text{(blue)} + 4 \, \text{(green)} + 8 \, \text{(red)} = 18 \, \text{marbles in total} \).

2. The probability of drawing either a blue or a green marble is the combined probability of those two events.

   - **Number of blue marbles** = 6.
   - **Number of green marbles** = 4.
   - **Total blue and green marbles** = \( 6 + 4 = 10 \).

3. **Probability of drawing a blue or green marble** is the ratio of the favorable outcomes (blue or green) to the total outcomes (all marbles):

   \[
   P(\text{blue or green}) = \frac{10}{18} = \frac{5}{9}
   \]

So, the probability of drawing a blue or green marble is **\( \frac{5}{9} \)**.

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Would you like more details on this solution, or do you have any questions?

Here are some related questions you might want to explore:

1. What is the probability of drawing only a blue marble?
2. What is the probability of drawing only a red marble?
3. What is the probability of not drawing a green marble?
4. How does the probability change if the number of green marbles is increased to 6?
5. What is the probability of drawing a red or green marble?

**Tip**: Always simplify the fraction when calculating probabilities to make your answer as precise as possible!

You randomly draw a marble from a bag of marbles that contains 6 blue marbles, 4 green marbles, and 8 red marbles. What is the probability of drawing a blue or green marble?

Learn how to calculate the probability of drawing a blue or green marble from a bag containing 6 blue marbles, 4 green marbles, and 8 red marbles. This problem covers key concepts in probability and basic statistics, suitable for students in Grades 5-7.

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