https://r2.erweima.ai/mathbot/image/1725920170670xht4iirn.jpg

https://r2.erweima.ai/mathbot/image/1725920170670g88uokhh.jpg

https://r2.erweima.ai/mathbot/image/1725920170670kx0qbhdd.jpg

It seems that there's an issue with recognizing Spanish language characters at the moment. I will switch to extracting text in English instead, which should capture much of the content since the handwriting involves a lot of mathematical notation. Let me attempt that.Here's the extracted text from the three images you uploaded. Due to the handwriting and the quality of the extraction, some characters may appear incorrect, but I'll transcribe the content as close to the original as possible. Feel free to ask for clarification or correction in certain areas if needed:

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**Image 1:**
```
En un circuito de corriente alterna se encuentran conectados en serie, una bobina de 2.65×10² H, un condensador cuya capacidad es 1.00×10⁻² F y una resistencia de 10Ω. Si se conecta el circuito a una línea de diferencia de potencial eficaz igual a 100 V, con una frecuencia de 60 ciclos/s, calcular la diferencia de potencial entre los extremos de cada elemento en el circuito. Figura 11.22.

V = 100 V ∠ 0°
F = 60 Hz

Z_L = ?
Z_R = ?
Z_C = ?

XL = ωL
L = 2.65 H
ω = 2πf = 2π(60/s)

ω = 377.99 s⁻¹ ≈ 377 s⁻¹
XL = 377.99 s⁻¹ * 2.65 H
XL = 999.405 Ω
```

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**Image 2:**
```
Z_L = j999.405 Ω
Z_R = 10 Ω
Z_C = 1/(ωC)

XC = 1 / (377.99 s⁻¹ * 1.00 × 10⁻² F)
XC = 25.02 Ω

Z_C = -j25.02 Ω

Z_T = Z_L + Z_R + Z_C
Z_T = j999.405 Ω + 10 Ω - j25.02 Ω

Z_T = (10Ω + j999.405Ω - j25.02Ω)
Z_T = √(10² + (999.405 - 25.02)²) ∠ atan[(999.405 - 25.02)/10]

Z_T ≈ 999.879.48 Ω ∠ 89.94°

I = V / Z_T
I = (100V ∠ 0°) / (999.879.48 Ω ∠ 89.94°)

I ≈ 0.001 A ∠ -89.94°
```

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**Image 3:**
```
V_L = I * Z_L
V_L = 0.001 A ∠ -89.94° * j999.405 Ω ∠ 90°
V_L ≈ 0.999405 V ∠ 0°

V_R = I * Z_R
V_R = 0.001 A ∠ -89.94° * 10 Ω ∠ 0°
V_R ≈ 0.01 V ∠ -89.94°

V_C = I * Z_C
V_C = 0.001 A ∠ -89.94° * -j25.02 Ω ∠ -90°
V_C ≈ 0.025 V ∠ -179.94°
```

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Would you like more detailed explanations or corrections? Feel free to ask if you have any questions.

Here are five related questions to consider:
1. What is the physical meaning of inductive reactance (XL)?
2. How does the total impedance (Z_T) affect the current in an AC circuit?
3. Why is the voltage across the capacitor out of phase with the current?
4. How does the frequency of the AC source impact the impedance of the capacitor?
5. What would happen to the current if the resistance in the circuit were increased?

**Tip**: In AC circuits, remember that inductors and capacitors create phase shifts between voltage and current due to their reactive nature!

En un circuito de corriente alterna se encuentran conectados en serie, una bobina de 2.65×10² H, un condensador cuya capacidad es 1.00×10⁻² F y una resistencia de 10Ω. Si se conecta el circuito a una línea de diferencia de potencial eficaz igual a 100 V, con una frecuencia de 60 ciclos/s, calcular la diferencia de potencial entre los extremos de cada elemento en el circuito.

Learn how to calculate the impedance and voltage drops across the inductor, capacitor, and resistor in a series AC circuit. The problem involves a 2.65 H inductor, a 1.00×10⁻² F capacitor, and a 10Ω resistor, connected to a 100V source with a frequency of 60 Hz. Detailed step-by-step solutions are provided, suitable for electrical engineering students.

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